Answer:
See below
Step-by-step explanation:
![\sqrt[3]{49} = 3.65930571002 \approx3.66 \\ \\ so \: \sqrt[3]{49} should \: lie \: at \: 3.6 \: which \: \\ fall \: between \: 3 \: and \: 4.](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B49%7D%20%20%3D%203.65930571002%20%5Capprox3.66%20%5C%5C%20%20%5C%5C%20so%20%5C%3A%20%20%5Csqrt%5B3%5D%7B49%7D%20should%20%5C%3A%20lie%20%5C%3A%20at%20%5C%3A%203.6%20%5C%3A%20which%20%5C%3A%20%20%5C%5C%20fall%20%5C%3A%20between%20%5C%3A%203%20%5C%3A%20and%20%5C%3A%204.)
Actually Lin did a mistake, she obtained square root and not cube root.
Given that the dealer sells a dozen tires for $240, every 3-tire set costs $60. There are six 2-tire sets in a dozen. Thus, his total revenue should be $360. The total profit is the difference between the total revenue and the total cost. The answer is therefore, the first choice, $120.
This question is incomplete, the complete question is;
For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?
Answer: the value of k = 2
Step-by-step explanation:
Given that;
a > 12
b < 20
a < b
If b = 7k
Now if k = 1 {b = 7k = 7}
b would be equal to 7 but b has to be greater than 20
IT CANT BE
if k = 2 { b = 7k = 14}
b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,
a has to be less than than b ( 12 < 14 )
IT IS
if k = 3 {b = 7k = 21}
b would be equal to 21, so b is greater than 20 and a is less than 21
IT CANT BE
Therefore the value of k = 2
The answer is 4x-6. Good luck! :D
Hope this helps!, I have to have more than 20 characters so ignore this!