A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
since isosceles has 2 sides that are equal then,
270 - 108 = 162
divide 162 by 2
162 ÷ 2 = 81
so, C
Answer: I'll give you both the percentage and dollar amount. 75% = $144
Step-by-step explanation: first, I added up all the percentages to total 75%. then I took the total sales, and divided that by .75 (75% in decimal form), so:
1940 x .75 = 1455
1940 - 1455 = 144
Answer:
Macaron are the best
Step-by-step explanation:
