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3 years ago

12

Delia can buy 3 identical sweatshirts for a total of $30. How much would it cost if she were to buy 4 of the same sweatshirts at

the same price per sweatshirt?

1 answer:

emmainna [20.7K]3 years ago

7 0

$30/ 3 sweatshirts = $10 /shirt

$ 10/shirt * 4 shirts = $40

It would cost $40

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Simplify and express the result in power notation with positive exponent

Molodets [167]

Answer:

3²

Step-by-step explanation:

Given expression:

$\sf (3^{-3} \div 3^{-10}) \times 3^{-5}$

Following the <u>order of operations</u>, carry out the calculations inside the parentheses first.

$\textsf{Apply the quotient exponent rule} \quad a^b \div a^c=a^{b-c}:$

$\implies \sf 3^{-3-(-10)} \times 3^{-5}$

$\implies \sf 3^{-3+10} \times 3^{-5}$

$\implies \sf 3^{7} \times 3^{-5}$

$\textsf{Apply the product exponent rule} \quad a^b \times a^c=a^{b+c}:$

$\sf \implies 3^{7+(-5)}$

$\sf \implies 3^{7-5}$

$\sf \implies 3^2$

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1 year ago

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Add the following rational number =<br> 3/11 and -5/12

tatiyna

Answer:

-19/132

Step-by-step explanation:

To add fractions, find the lowest common multiple of the two denominators and multiply accordingly to make both denominators the same. In this case, the lowest common multiple of 11 and 12 is 132, so we need to multiply the first number by 12 and the second by 11. So we get $\frac{36}{132} + (-\frac{55}{132} )$ = $\frac{36-55}{132}$ = $\frac{-19}{32}$ $-\frac{19}{132}$

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2 years ago

Which is greater 9.018 or 9.108

professor190 [17]

Answer:

9.108

You only need to look at the 10nths place to determine which number is larger

Step-by-step explanation:

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2 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

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