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tekilochka [14]
3 years ago
13

A beverage company makes 100% cranapple juice, which is made up of

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
Answer: 54-fluid ounces
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Mixed Review
Eduardwww [97]
1. b = $95.94 / 6
       = $15.99

    t = $15.99 / 20
      = $0.80

2. A: $1.28 / 8 = $0.16 per oz
    B: $1.68 / 12 = $0.14 per oz 

    Difference: $0.02 per oz
6 0
3 years ago
Read 2 more answers
Jamie purchased a DVD that was on sale for 15% off. The sales tax in her county is 5%. Let y represent the original price of the
Triss [41]

Answer:

1.05(0.85y)

Step-by-step explanation:

15% off so .85y and a 5% tax so 1.05(.85y)

6 0
3 years ago
Read 2 more answers
The formula for the volume of a cylinder is v= 3.14r^2h. A cylinder has a volume of 300x feet ^3 and a radius of 5 feet
Fudgin [204]

Answer:

Height = 3.82

Step-by-step explanation:

(3.14)(5)²

(3.14)(25)

= 78.5

300 = 78.5h

300/78.5 = 78.5h/78.5

h = 3.821656051 or approximately 3.82

7 0
3 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
4 years ago
Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height
BARSIC [14]

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

3 0
4 years ago
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