Solution: Let 
be the number of adult ticket's.
The number of child ticket 
We are given, that an adult ticket cost's $10 and child ticket costs $6. Also the church luncheon made $842.
Therefore,
Therefore, the number of adult ticket's sold = 35
And the number of child ticket's sold = 2 x 35 + 12 = 70 + 12 = 82
The first thing I would do is write an expression for the amount the limo will cost in terms of the number of miles you drive. In this scenario, the cost=.15(mile)+700.
Now is the question, should the limo cost more or less than $750 to stay on budget? The answer is you should spend less than $750. Thus, when writing the inequality, or .15m+700<750. However, you could spend exactly $750 so you inequality should really be .15m+700≤750. Now you just need to solve this for the number of miles you can drive.
First, subtract 700 from both sides and you are left with .15m≤50
Then divide both sides by .15 and you are left with m ≤ 333.33. Thus, the limo can only travel 333.33 miles.
Answer:
c-25/ m
hope that helps
Step-by-step explanation:
Algebreic manipulation, watch Khan acadmy.
Answer:
(-2,4) and (2,0)
Step-by-step explanation:
The graphical solution to the system of equations is simply the point(s) where the graphs of the function intersect or cross each other.
The graphs of the function can be found in the attachment below;
From the graph, the functions intersect at ;
(-2,4) and (2,0)
Answer: 1.33-inch wheels
Step-by-step explanation:
The scale factor is 1 : 12. (i.e 12 inches on the actual is represented by one unit on the scale model)
So, If the actual car has 16-inch wheels,
The size of the wheels on the scale model will be 16-inch / 12 = 1.33-inch
Thus, Thom's car will have 1.33-inch wheels
