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kolezko [41]
3 years ago
11

What activity behind the wheel involves all three types of distractions (visual, manual, and cognitive) and is the most alarming

?
Advanced Placement (AP)
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

The most alarming of these distractions is the one that requires the driver to take his visual, manual and cognitive attention away from driving: TEXTING.

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Rufina [12.5K]

Answer:

x = 68 degree

y = 112 degree

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3 0
3 years ago
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Jillian plays darts professionally. Suppose that she has a 20\%20%20, percent probability of hitting bullseye when she aims for
vekshin1

Probabilities are used to determine the chances of hitting the bullseye

<h3>How to plot the graph</h3>

The sample space is given as:

Sample space = {NN, NB, BN, BB}

From the sample space above, we have the following theoretical values

P(N = 2) = 0.25

P(N = 1) = 0.50

P(N = 0) = 0.25

Next, we plot the graph of the theoretical probability distribution

Where:

  • The x-axis represents the number of hits
  • The y-axis represents the probability

See attachment for the graph

Read more about probabilities at:

brainly.com/question/25870256

6 0
2 years ago
Hercules went to what king to be a slave?
serious [3.7K]

Answer:

King Of Mycenae

Explanation:

As punishment for killing his family, Hercules went to the King of Mycenae, and offered to be his slave.

7 0
4 years ago
Is Water Wet? WILL GIVE BRAINIEST ANSWER!!!!!!!!
lesya692 [45]

Answer:

no

Explanation:

because water is already a liquid substance which can wet things

8 0
3 years ago
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The mass of the Sun is 2 × 1030 kg, and the distance between Neptune and the Sun is 30 AU. What is the orbital period of Neptune
Volgvan
<h2>Orbital Period:</h2>
  • To answer this problem, we must employ the gravitational notion and equation. We already know that gravitational force provides the required centripetal force for orbital motion. As a result of matching gravitational and centripetal forces, we may get the equation for orbital time period.
<h2>Answer and Explanation:</h2><h3>Given:</h3>
  • Mass of Sun (M) = 1.99 * 10^30 Kg
  • Orbital radius of the Neptune
  • (R) = 30 A.U. = 30 * (1.496 * 10^11) m
  • R = 44.88 * 10^11 m

Now we know that the time period is given by

T^2 = 4π^2R^3/GM

T^2 = 4π^2*(44.88*10^11)^3/6.67*10^-11*(1.99*10^30)

T = 5.19 * 10^9 s

Now we know that

1 year = 3.154 * 10^7 s

Therefore, T = 5.19*10^9 s/ 3.154 * 10^7 (s/year)

T = 164.4 year

3 0
2 years ago
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