Yes they are
. 90/150= 3/5
so 45/75 and 3/5.
2(x + 2) + 2 = 2(x + 3) + 1
2x + 4 + 2 = 2x + 6 + 1
2x + 6 = 2x + 7 - NO SOLUTION
(subtract 2x from both sides, then 6 = 7 FALSE)
2x + 3(x + 5) = 5(x – 3)
2x + 3x + 15 = 5x - 15
5x + 15 = 5x - 15 - NO SOLUTION
4(x + 3) = x + 12
4x + 12 = x + 12 - ONE SOLUTION
4 – (2x + 5) = (–4x – 2)
4 - 2x - 5 = -4x - 2
-2x - 1 = -4x - 2 - ONE SOLUTION
5(x + 4) – x = 4(x + 5) – 1
5x + 20 - x = 4x + 20 - 1
4x + 20 = 4x + 19 - NO SOLUTION
Answer:

Step-by-step explanation:
We need to solve 
We know that,

Using the above formula,
![(8m-3n)^2 - (4m+3n)^2=(8m)^2+(3n)^2-2(8m)(3n)-[(4m)^2+(3n)^2+2(4m)(3n)]\\\\=64m^2+9n^2-48mn-(16m^2+9n^2+24mn)\\\\=64m^2+9n^2-48mn-16m^2-9n^2-24mn\\\\=48m^2-48mn-24mn\\\\=48m^2-72mn](https://tex.z-dn.net/?f=%288m-3n%29%5E2%20-%20%284m%2B3n%29%5E2%3D%288m%29%5E2%2B%283n%29%5E2-2%288m%29%283n%29-%5B%284m%29%5E2%2B%283n%29%5E2%2B2%284m%29%283n%29%5D%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-%2816m%5E2%2B9n%5E2%2B24mn%29%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-16m%5E2-9n%5E2-24mn%5C%5C%5C%5C%3D48m%5E2-48mn-24mn%5C%5C%5C%5C%3D48m%5E2-72mn)
So, the final answer is
.
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