Answer: 30
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You visited this page on 12/2/21.
Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
I assume this is the intersection of two lines, i.e. -1/2y is (-1/2)y. Please tell me if it's really -1/(2y).
(-1/2)y=(1/2)x+5
Multiplying both sides by -2
y = - x - 10
The other equation is
y = 2x + 2
We can equate them to find the meet
y = - x - 10 = 2x + 2
-3x = 12
x = -4
y = 2x + 2 = -6
Check: (-1/2)y=3, (1/2)x+5=3, equal, good
2x+2=2(-4)+2=-6=y, good
Answer: x=-4, y=-6
Answer:
he used 5 1/3 everything else is to low or high