This could be rephrased as:
You start with 100 grams of a substance. One year later you have 70 grams. What is the half-life?
We need this formula:
half-life = (time * natural log (2)) / natural log (beginning amount / ending amt)
half-life = (1 year * .69315) / natural log (100 / 70)
half-life = (.69315) / 0.35667494396
half-life = 1.9433661145 years
Rounding to nearest year half-life = 2 years
Sourse: https://www.1728.org/halflif2.htm
(See problem 3)
Answer:
(- 5, 1 )
Step-by-step explanation:
- 6x - 14y = 16 → (1)
- 2x + 7y = 17 → (2)
Multiplying (2) by - 3 and adding to (1) will eliminate the x- term
6x - 21y = - 51 → (3)
Add (1) and (3) term by term to eliminate x
0 - 35y = - 35
- 35y = - 35 ( divide both sides by - 35 )
y = 1
Substitute y = 1 into either of the 2 equations and solve for x
Substituting into (1)
- 6x - 14(1) = 16
- 6x - 14 = 16 ( add 14 to both sides )
- 6x = 30 ( divide both sides by - 6 )
x = - 5
solution is (- 5, 1 )
Answer:
q=-5
Step-by-step explanation:
8q+6=4q-14
Remove q from one side
8q+6=4q-14
-4q -4q
4q+6=-14
Remove 6 from both sides
4q+6=-14
-6 -6
4q=-20
Divide 4 to isolate q
4q/4=-20/4
q=-5
Answer:
The equation is f-1(x) = x - 7.
Domain of the inverse is [49, 2025) and the range is (0, 38).
Step-by-step explanation:
The range of the function is the domain of the inverse, and the domain of the function is the range of the inverse.
The equation of the inverse is x - 7.