Put it in reverse and ease off of the breaks
Multiplying both sides of a rational equation by a variable expression introduces the possibility of extraneous solutions. Therefore, we must check the solutions against the set of restrictions. If a solution is a restriction, then it is not part of the domain and is extraneous.
The soluition set is (-3,5) and a normal ordered pair reads (x,y). So that means 5 = [_]x-10
-Add 10 to both sides
15 = [_]x
-And we know the value of x so lets sub that in.
15 = [_](-3)
-And now we divide by -3
-5 = [_]
Next we have 3x-[_]y=-19
-Lets start this buy substituting values of x and y into the equation again.
3(-3)-[_](5)=-19
-Simplify
-9 - [_](5) = -19
-Move the (-9) by adding 9 to both sides
-[_](5) = -10
-divide by 5 = -2
-(1)[_] = -2
[_] = 2
Answer:
y = 3
x = 2
Step-by-step explanation:
x+y=5 == -2x - 2y = -10
2x-y = 1 == 2x - y = 1 +
-------------------
-3y = -9
<u>y = 3</u>
x + y = 5
x + 3 = 5
<u>x = 2</u>
Answer:
B
Step-by-step explanation:
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