The value of integration of y=16-
from x=-1 to x=1 is 94/3.
Given the equation y=16-
and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16-
from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-
.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)-
-16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16-
from x=-1 to x=1 is 94/3.
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B looks the most reasonable
Answer:
x= −16.8
Step-by-step explanation:
Answer:
Answer: The answer is option B.
Step-by-step explanation:
Here,
We have,



So, it's true; and it lies in quadrant 1 and 4.
The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.
B in has the intersection with quadrant 1 and 3