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3 years ago

Given y2 + 5y - 6 = (y + p)(y +q) find the values of p and q.

Mathematics

1 answer:

finlep [7]3 years ago

5 0

Answer:

p = 6, q = - 1

Step-by-step explanation:

Factor the left side and compare to right side

y² + 5y - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the y- term (+ 5)

The factors are + 6 and - 1, since

6 × - 1 = - 6 and 6 - 1 = + 5, thus

y² + 5y - 6 = (y + 6)(y - 1)

Compare with (y + p)(y + q) , then

p = 6 and q = - 1

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2 years ago

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4 years ago

Read 2 more answers

What is the radical form of the expression (2x^4y^5)^3/8

s344n2d4d5 [400]

We are given expression: $(2x^4y^5)^{3/8}$

Let us distribute 3/8 over exponents in parenthesis, we get

$(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})$

$= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )$

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

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Now, we could write inside expression of parenthesis in radical form.

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3 years ago

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Luda [366]

Answer:

$\dfrac{7\pi}{18}$

Step by step explanation:

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2 years ago