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3 years ago

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What is the value of v?

1 answer:

Assoli18 [71]3 years ago

7 0

I hope this helps you

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It requires 15 gallons of mulch to cover 5 flowerbeds. How many gallons are needed to cover 7 flowerbeds?

vaieri [72.5K]

21 gallons at least are required

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3 years ago

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What is 0.0000091 written in scientific notation

zaharov [31]

The goal of writing a number in scientific notation is to have a decimal number, with one digit to the left of the decimal point, followed by a <span>×⨯</span><span>1010</span> to some power. To format the number this way, multiply the <span>0.00000910.0000091</span> by <span>1010</span> <span><span>−6</span><span>-6</span></span> times, making it <span>9.19.1</span>. Each multiplication by <span>1010</span> moves the decimal point one digit to the left, but in order to keep the same number, multiply <span>9.19.1</span> by <span><span>10<span>−6</span></span><span>10<span>-6</span></span></span>.<span>9.1×<span>10<span>−<span>6</span></span></span></span>

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3 years ago

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The price of a bag of candy is a linear function of the amount of candy in the bag. A bag containing 25 pieces costs $0.99 and a

OlgaM077 [116]

Answer:

About 152 pieces of candy

Step-by-step explanation:

Set up equal proportions to solve for the $5.99 bag.

We know that 24 pieces = .99, so

$\frac{25 pieces}{.99 dollars} = \frac{x pieces}{5.99 dollars}$

Make sure to keep the pieces on top, and the dollars on bottom (or vice versa). If your units are messed up, it will not work.

Cross-multiply.

25(5.99) = .99x

Simplify.

149.75 = .99x

Divide both sides by .99.

x = 151.26 = about 151 pieces of candy

7 0

3 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

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3 years ago

What is 1034÷22 ?<br><img src="https://tex.z-dn.net/?f=1034%20%5Cdiv%2022%20" id="TexFormula1" title="1034 \div 22 " alt="1034 \

Mrrafil [7]

The answer would be 47

3 0

3 years ago

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