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3 years ago

Help!! Algebra 1!! sorry if the picture is bad

Mathematics

1 answer:

dimulka [17.4K]3 years ago

3 0

Answer:

The first one matches with f(x)√x because a square root cannot be negative

The second one matches with f(x)=√(x-5) because the square root would be negative if it were less than five.

The third one matches with f(x)=8x because there is nothing that makes it a not possible answer

The last one matches with 7/(x-8) because there cannot be a denominator of zero.

You might be interested in

Solve for x: x+4(x+4+3x) = 8(8+19)

densk [106]

X + 4( x + 4 + 3x) = 8(8 +19)
x + 4 (4x + 4) = 8(27)
x + 16x + 16 = 216
17x + 16 (-16) = 216 (-16)
17x = 200
17x/17 = 200/17
x = 11.76

x = 11.76 is your answer

hope this helps

4 0

3 years ago

Helppppp me thank you

Basile [38]

Answer:

y = 5/6x + 4

Step-by-step explanation:

y = mx + b

b = 4 because when x = 0, y = 4

m = (y2 -y1) / (x2 - x1)

where two points on the equation are (x1, y1) & (x2, y2)

Let's pick points (6,9) & (-6,-1)

m = (-1 - 9) / (-6 - 6)

m = -10 / -12 = 5/6

6 0

3 years ago

6x + 8y + 6 ; x = 2 , y = 6

olga_2 [115]

Answer:

Step-by-step explanation:

6x + 8y + 6

x=2

y=6

Replace the letters with the numbers:

6(2) + 8(6) +6

= 12 +48 + 6

= 66

7 0

3 years ago

Evaluate x + 2(-5)<br> when x = -17

Mariulka [41]

Answer: -27

Step-by-step explanation: -17+2(-5)

2(-5)= -10

-10 + -17 = -27

8 0

3 years ago

A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weight

a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 lb, and the standard deviation of the weights is s=1.968 lb.

This means that $\mu = 2.088, \sigma = 1.968$

a. What is the difference between the weight of 5.31 lb and the mean of the weights?

This is $X - \mu = 5.31 - 2.088 = 3.222$

The difference is of 3.222 lbs.

b. How many standard deviations is that [the difference found in part (a)]?

This is the z-score. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.31 - 2.088}{1.968}$

$Z = 1.64$

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

5 0

3 years ago