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Angelina_Jolie [31]
3 years ago
5

Help!! Algebra 1!! sorry if the picture is bad

Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

The first one matches with f(x)√x because a square root cannot be negative

The second one matches with f(x)=√(x-5) because the square root would be negative if it were less than five.

The third one matches with f(x)=8x because there is nothing that makes it a not possible answer

The last one matches with 7/(x-8) because there cannot be a denominator of zero.

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Slice for 5x+c=k for x
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Answer:

A - x = (k-c)/5

Step-by-step explanation:

To solve this problem, we would solve for x like we would in 2x = 6 :

5x + c = k

5x = k-c (subtract c from both sides)

x = k/5 - c/5 (divide 5 on both sides)

x = (k-c)/5 (simplify)

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Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
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Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


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