Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
1.) He still owes $100 of debt
2.) 1 rose would be .75 cents and 1 carnation would be .90 cents
3.) C 8 and 3/8
Step by Step explanation
(/ means divided by in the first 2 equations but / in the last question is for the fractions.)
1.) _(1,500 / 3 =500. 1,500 - 500 =1,000 / 5 =200 x 3 =600. 700 - 600 =$100)
2.)_(1.50/2 =.75 cents. 2.70/3 =.90 cents.)
3.) i first added the fractions ( i equalized them) then i added the whole numbers (the u in the equation was to separate the whole num. and fraction )
Before i equalized it: (6u3/4 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)
After i equalized it: (6u6/8 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)
Answer:
<h3>The solution is 480 bricks.</h3>
Step-by-step explanation:
We are given that number of rows of bricks in a wall = 15 rows.
Number of bricks in a row = 32 bricks.
In order to find the total number of bricks, we need to multiply number of rows with number of bricks in a row.
Total number of bricks in 15 rows = 15 × 32 = 480 bricks.
Therefore, will Chin-li will need 480 bricks.
<h3>The solution is 480 bricks.</h3>
Answer:
3 milkshakes and 3 sundaes
Step-by-step explanation:
3 * 5 = $15 + 3 * 2 = $21