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Andreas93 [3]
3 years ago
8

What’s this answer? I really need help I have a F

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

The distance between the center of the circle and the center of the triangle is 8 units

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Convert 23 days to weeks and days?
dezoksy [38]

Answer:

3 weeks and 2 days

Step-by-step explanation:

6 0
3 years ago
A small plane is flying a banner in the shape of a rectangle. The area of the banner is 144 square feet . The width of the banne
Margarita [4]

Answer:

The answer to your question is width = 6 ft; length = 24 ft

Step-by-step explanation:

Data

Area = 144 ft²

width = w

length = l

The width is 1/4 of the length

Formula

Area = width x length = w x l

Length = 4 width     l = 4w

Process

1.- Substitute length in the first equation

                       Area = w(4w)

Simplify

                       Area = 4w²

2.- Solve for w

                      w = \sqrt{\frac{Area}{4}}

Substitution

                      w = \sqrt{\frac{144}{4}}

Simplification

                      w = \sqrt{36}

Result

                      w = 6 ft

3.- Find l

                       l = 4(6)

                       l = 24 ft

8 0
4 years ago
Is there another word for thesourous?????
scoundrel [369]

Answer:

   reference book.

   glossary.

   lexicon.

   onomasticon.

   terminology.

   vocabulary.

   language reference book.

   sourcebook.

Step-by-step explanation:

5 0
2 years ago
Please give correct answer!
Roman55 [17]
If the object is a true parallelogram, then p=36.4/5.2=7 yd.
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3 0
4 years ago
Many elementary school students in a school district currently have ear infections. A random sample of children in two different
Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school n_1 = 42

sample size for the second school n_2  = 34

so 16 out of 42 i.e x_1 = 16 and 18 out of 34 i.e x_2 = 18 have ear infection.

the proportion of students with ear infection Is as follows:

\hat p_1 = \dfrac{16}{42} = 0.38095

\hat p_2 = \dfrac{18}{34}  =  0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}

\bar p = \dfrac{16 +18}{42 +34}

\bar p = \dfrac{34}{76}

\bar p = 0.447368

\bar p + \bar  q = 1 \\ \\ \bar q = 1 -\bar  p \\  \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632

The pooled standard error can be computed by using the formula:

S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} +  \dfrac{\bar p \bar p}{n_2} }

S.E = \sqrt{ \dfrac{  0.447368 *  0.552632}{ 42} +  \dfrac{ 0.447368 *  0.447368}{34} }

S.E = \sqrt{ \dfrac{  0.2472298726}{ 42} +  \dfrac{ 0.2001381274}{34} }

S.E = \sqrt{ 0.01177284105}

S.E = 0.1085

The test statistics is ;

z = \dfrac{\hat p_1 - \hat p_2}{S.E}

z = \dfrac{0.38095- 0.5294}{0.1085}

z = \dfrac{-0.14845}{0.1085}

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0
4 years ago
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