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Anastasy [175]
3 years ago
10

What is the area of the parallelogram? 80 cm 2 40 cm 2 29 cm 58 cm 2

Mathematics
2 answers:
sergey [27]3 years ago
4 0

Answer:

A = 80 cm^2

Step-by-step explanation:

The area of a parallelogram is

A = bh

A = 16*5

A = 80 cm^2

I am Lyosha [343]3 years ago
3 0

Answer:

80 square centimeters

Step-by-step explanation:

The area of a parallelogram is the product of the height and the base length. In this case, that is 6*15=80 square centimeters. Hope this helps!

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Alexxx [7]

Answer:

The probability of it being greater than 6 is 3/4.

Step-by-step explanation:

there are 4 outcomes, and 6 is only one of them. 3 are greater than 6, so 4 out of the 4 times the number will be greater than 6.

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Answer:

There is no specific set way to move on.

Step-by-step explanation:

In most cases, I would say: time. With time wounds will fade; but scars will always be left behind. Do stuff that distracts you, like hobbies and devote yourself to them. Soon enough you'll forget what even happened to you.

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Find the height of the pyramid round answer to the nearest meter
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the figure at the right shows the dimensions of the garden in Marissa's back yard. What is the area of the garden?
vodka [1.7K]

The area of the garden is 74 square feet

<h3>How to determine the area of the garden?</h3>

The complete question is added as an attachment

From the attached figure, we have the following shapes and dimensions:

  • Rectangle: 10 by 5 feet
  • Trapezoid: Bases = 10 and 6; Height = 3

The rectangular area is

A1 = 10 * 5

Evaluate

A1 = 50

The area of the trapezoid is

A2 = 0.5 * Sum of parallel bases * height

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A2 = 0.5 * (10 + 6) * 3

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Total = A1 + A2

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Total = 50 + 24

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5 0
10 months ago
A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03​% chlorine. Starting at tequals​0, city water conta
Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is  

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.  

Remember, 1 h = 60 minutes. The initial value problem is  

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x =  - 6* 10⁻⁴*(3x - 10⁻¹)               x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us  

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C    or    |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).  

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then  

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If  t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

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