Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Answer:
12/13
Step-by-step explanation:
m=(-6-6)/(-7-6)=-12/-13=12/13
Answer:
415/619
Step-by-step explanation:
619 is a prime number, so the fraction is in simplest form already.
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
Answer:
b includes a in it this is a full sentense