Question

Datguy323 is going to complain again. What's the variables for: 3D7" id="TexFormula1" title="x^2+y^2=29\\x+y=7" alt="x^2+y^2=29\\x+y=7" align="absmiddle" class="latex-formula">
y<4

Answer 1

Answer: :o I FINALLY MADE IT

(5, 2)

x = 5

y = 2

Step-by-step explanation:

First, I graphed both equations.  They meet at the points (5,2) and (2,5).  Because y < 5, the solution is (5, 2)

Hope it helps <3

Answer 2

Answer:

$x=5\\y=2$

Step-by-step explanation:

$x^2 +y^2 =29$

$x+y=7$

Solve for x in the second equation.

$x+y=7$

$x+y-y=7-y$

$x=7-y$

Plug in the value for x in the first equation and solve for y.

$(7-y)^2 +y^2 =29$

$y^2-14y+49+y^2 =29$

$2y^2-14y+20=0$

$2(y-2)(y-5)=0$

$2(y-2)=0\\y-2=0\\y=2$

$y-5=0\\y=5$

$y$

$y=2$

$y\neq 5$

Plug y as 2 in the second equation and solve for x.

$x+y=7$

$x=7-y$

$x=7-2$

$x=5$