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photoshop1234 [79]
3 years ago
5

Among 46​- to 51​-year-olds, 28​% say they have called a talk show while under the influence of peer pressurepeer pressure. Supp

ose sevenseven 46​- to 51​-year-olds are selected at random. ​(a) What is the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressurepeer pressure​? ​(b) What is the probability that at least one has called nbspcalled a talk showa talk show while under the influence of peer pressurepeer pressure​?
Mathematics
1 answer:
sasho [114]3 years ago
3 0

Answer:

0.8997, 0.9999

Step-by-step explanation:

Given that among 46​- to 51​-year-olds, 28​% say they have called a talk show while under the influence of peer pressure.

i.e. X no of people who say they have called a talk show while under the influence of peer pressure is binomial with p = 0.28

Each person is independent of the other and there are only two outcomes

n =7

a) the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

=P(Y\geq 1) where Y is binomial with p = 0.72

= 1-(1-0.72)^7\\=0.9999

b) the probability that at least one has  called a talk showcalled a talk show while under the influence of peer pressurepeer pressurethe probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure

=P(x\geq 1) =1-P(0)\\= 1-(1-0.28)^7\\=0.8997

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Answer:

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Simplify the following expression by combining like terms.<br> 3x + 4x² - 7x+ 9x2
EleoNora [17]

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13x² - 4x

Step-by-step explanation:

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= (4x² + 9x² ) + (3x - 7x)

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2 years ago
Which measurement is most accurate to describe the width of a penny?
klasskru [66]

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19 mm

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3 years ago
Please help me on these questions and explain it thanks
BlackZzzverrR [31]
For problem 2:

The answer would be B) Car A travels more miles per gallon of fuel than Car B.

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For problem 3:

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8 0
3 years ago
Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
3 years ago
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