Among 46- to 51-year-olds, 28% say they have called a talk show while under the influence of peer pressurepeer pressure. Supp
ose sevenseven 46- to 51-year-olds are selected at random. (a) What is the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressurepeer pressure? (b) What is the probability that at least one has called nbspcalled a talk showa talk show while under the influence of peer pressurepeer pressure?
Given that among 46- to 51-year-olds, 28% say they have called a talk show while under the influence of peer pressure.
i.e. X no of people who say they have called a talk show while under the influence of peer pressure is binomial with p = 0.28
Each person is independent of the other and there are only two outcomes
n =7
a) the probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure
= where Y is binomial with p = 0.72
=
b) the probability that at least one has called a talk showcalled a talk show while under the influence of peer pressurepeer pressurethe probability that at least one has not called a talk showcalled a talk show while under the influence of peer pressure
Because the order of operations (Bodmas or Pedmas) tells you to add from left to right. So you would do 18.79 + 2.11 = 20.9, then you would do 20.90 + 1.92 (Add 0 at the end of 20.9) = 22.81. Then you will add 22.81 + 17.28 = 40.1. So your answer is 40.1. Hope this helps!