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gayaneshka [121]
3 years ago
11

A manufacturing company uses an acceptance scheme on production items before they are shipped. The plan is a two-stage one. Boxe

s of 25 are readied for shipment and a sample of 3 is tested for defectives. If any defectives are found, the entire box is sent back, for 100 percent screening. If no defectives are found, the box is shipped.
Q: Now suppose the manufacturing company decides to change its acceptance scheme. Under this new scheme an inspector takes one at random, inspects it, and then replaces it in the box; a second inspector does likewise. Fianlly a third inspector goes through the same procedure. The box will not be shipped if any of the three find a defective.

ANSWER THE FOLLOWING. AND PLEASE EXPLAIN IN WORDS HOW TO SOLVE THIS PROBELM

a) What is the probability that a box containing 3 defectives will be shipped?

b) What is the probability that a box containing only 1 defective will be sent back for screening?
Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

WOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOW IDK

Step-by-step explanation:

LOL :)

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Step-by-step explanation:

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x = 300/√3

x = 100√3

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I need help badly please with number 2 ...help me .. please no links or I will report you
klasskru [66]

9514 1404 393

Answer:

  $62.74

Step-by-step explanation:

The annuity formula can be used to find the payment needed. Fill in the known values and solve for the unknown.

The future balance due to a series of payments is given by ...

  A = P(n/r)((1 +r/n)^(nt) -1)

where A is the account balance P is the payment made each period, n is the number of periods per year, r is the annual interest rate, and t is the number of years.

You have A = $20,000, r = 0.041, n = 12, t = 18 and you want to find P

  P = A(r/n)/((1 +r/n)^(nt) -1)

  P = $20,000(0.041/12)/((1 +0.041/12)^(12·18) -1) ≈ $62.74

A monthly payment of $62.74 is required.

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