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lisabon 2012 [21]
3 years ago
9

Find g(2) for the function, g(x)=−6x+8.

Mathematics
1 answer:
Sonja [21]3 years ago
4 0

Answer:

-4

Step-by-step explanation:

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How many ounces are in 2 ounces
VARVARA [1.3K]

Answer:

2 ounces are in 2 ounces

Step-by-step explanation:

5 0
3 years ago
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35 solve the following syste
blondinia [14]

Part A: The solution is (-0.923,5.692)

Part B: The point (3,7) is not in the solution set.

Explanation:

Part A: The given inequalities are 3 x+4 y>20 and x

The solution can be determined by solving the two inequalities by substitution method.

Changing inequalities to equality, we have,

x=3 y-18 and 3 x+4 y=20

Let us substitute x=3 y-18 in the equation 3 x+4 y=20 , we get,

3 (3y-18)+4 y=20

   9y-54+4y=20

                  13y=74

                     y=5.692

Substituting y=5.692 in x=3 y-18, we get,

x=3 (5.692)-18

  =17.076-18

x=-0.923

Thus, the solution set is (-0.923,5.692)

Part B: Now, we shall determine whether the point (3,7) is in the solution set.

Let us substitute the point (3,7) in the inequalities 3 x+4 y>20 and x, we get,

3 (3)+4 (7)>20

      9+28>20

            37>20

Also, substituting (3,7) in x, we get,

3

3

3

Since, the point (3,7) does not satisfy one of the inequality x , the solution set does not contain the point (3,7)

Thus, the point (3,7) is not in the solution set.

8 0
2 years ago
If f(x)=x-2 and g(x)=1/2x, find g(f(x))
Scilla [17]

Answer:

hello :

If f(x)=x-2 and g(x)=1/2x,

g(f(x)) = g ( x - 2 )

          = 1/2(x-2)

g(f(x)) = (1/2)x - 1



8 0
3 years ago
Read 2 more answers
A spherical balloon is inflating with helium at a rate of 64 pi StartFraction ft cubed Over min EndFraction . How fast is the​ b
olga2289 [7]

Answer:

The radius of the balloon is increasing at a rate of 4 feet per minute.

Step-by-step explanation:

We are given the following in the question:

\dfrac{dV}{dt} = 64\pi \dfrac{\text{ ft}^3}{\text{min}}

Volume of sphere is given by

V = \dfrac{4}{3}\pi r^3

where r is the radius of the balloon.

Instant radius, r = 2 ft

Rate of change of volume =

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt} =4\pi r^2\dfrac{dr}{dt}

Putting values, we get,

64\pi = 4\pi (2)^2\dfrac{dr}{dt}\\\\\Rightarrow \dfrac{dr}{dt} = 4

Thus, the radius of the balloon is increasing at a rate of 4 feet per minute.

5 0
3 years ago
49 - 3 + 9 times 8 divided by 2
irinina [24]

Answer:

82

Step-by-step explanation:

49 - 3 + 9 times 8 divided by 2

6 0
3 years ago
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