3(2x) + 4y(5)<br> what is the equivalent fraction <br><br><br><br> hurry please .

I need help with a word problem. Picture is below. Please help.

mars1129 [50]

I hope this helps you

2x+pi. x

7 0

3 years ago

PLEASE HELP!

Airida [17]

7 dollars each game and I know that because 10 would be 60 plus 16 which is way over and 5 would be 25 plus 16 which is incorrect 6 would be 30 which adding 16 would be 46. FINALLY ADDING 5 extra which is 7 times which is 35 plus 16 is 51.
Hope this helped
:D

4 0

3 years ago

16) Divide: −96 ÷ −12 = A) −8 B) −7 C) 6 D) 8

ira [324]

Answer:

It would be (D 8)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 65% chan

amm1812

Answer:

0.49

Step-by-step explanation:

We apply conditional probability to solve this question.

We have Events X and Events Y

P(X) = Probability Christine fails the course = ??? Unknown

P(Y) = Probability Christine finds a tutor

= 0.35

P(Y') = Probability Christine does not find a tutor = 1 - 0.35 = 0.75

P(X|Y) = Decrease in her probability of failing = 0.35

P(X|Y') = Probability that she will fail the course if she does not have a tutor

P(X) = P(X|Y) × P(Y) + P(X|Y') × P(Y')

P(X) = 0.35 × 0.75 + 0.65 × 0.35

P(X) = 0.2625 + 0.2275

P(X) = 0.49

The probability that Christine fails the course is 0.49

8 0

3 years ago

The city has an average of 13 days of rainfall for April.

zhenek [66]

Using the Poisson distribution, we have that:

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

For this problem, the mean is given as follows:

$\mu = 13$

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859$

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0$

$P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003$

$P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019$

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0

2 years ago

3(2x) + 4y(5) what is the equivalent fraction hurry please .