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3 years ago

A rectangle has a perimeter of 25 in. The length is four times the width. What are the dimensions of the rectangle

Mathematics

1 answer:

sladkih [1.3K]3 years ago

5 0

Answer:

L = 10 in

W = 2.5 in

Step-by-step explanation:

Let length be L and width be W

Perimeter = L + L + W + W

Perimeter =2L + 2W

given than length is 4 times the width, or

L = 4W (substitute this back into the perimeter equation above)

Perimeter =2L + 2W

Perimeter =2(4W) + 2W

Perimeter =8W + 2W

Perimeter = 10W

given that the perimeter is 25in

25 = 10W

W = 25 / 10 = 2.5 in (answer for width)

L = 4W = 4(2.5) = 10 in (answer for length)

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If I drive 8.5 laps around a circular race track and during that drive I go 32 mi, what is the radius of the track? Round to two

Black_prince [1.1K]

Answer: The radius of the track = 0.64 mi

Step-by-step explanation:

Fr circular track , Total distance covered around it = (Number of laps) x (Circumference)

As per given,

32 mi = 8 x (Circumference)

Circumference = $\dfrac{32\ mi}{8}=4\ mi$

Also, Circumference = $2\pi r$ , where r= radius so,

$2\pi r=4\ mi\\\\\Rightarrow\ r=\dfrac{4}{2\pi}\\\\\Rightarrow\ r=\dfrac{2}{\pi}$

Put $\pi= 3.14$

$r=\dfrac{2}{3.14}\approx0.64\ mi$

Hence, the radius of the track = 0.64 mi

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3 years ago

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Ira Lisetskai [31]

3 2/5 + 4 1/5
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The answer is 7 3/5
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4 years ago

Factor completely 2x2 - 18. Prime 2(x2 - 9) 2(x + 3)(x - 3) 2(x + 3)(x + 3)

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Answer:

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Step-by-step explanation:

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