Answer:
Answer(s): <u>15m</u>
<u>20(m-0.25m)</u>
Step-by-step explanation:
Answer:
about 3
Step-by-step explanation:
I know from experience
Let z = √(x^2 +2x +4).
Then your expression becomes
y = (z^2)^z
y = z^(2z)
And the derivative with respect to x is
y' = z^(2z)*(2z' +2ln(z)z')
= (2z')(1 +ln(z))(z^(2z))
Now
z' = (2x +2)/(2√(x^2 +2x +4)
= (x +1)/√(x^2 +2x +4)
So, your derivative is
y' = 2(x +1)/√(x^2 +2x +4) * (1 + (1/2)ln(x^2 +2x +4)) * (x^2 +2x +4)^√(x^2 +2x +4)
For x = 0, this becomes
2(1)/√4 * (1 +(1/2)ln(4)) * 4^√4
= 16*(1 + ln(2))
Down refers to the movement along the y axis and left and right refer to movement along the x axis. 20. down 2, no y movement 21. 5 to the left, no y movement 22. to the right 1, no y movement 23. 4 to the left, down 3 24. to the left 2 and up 2 25. 4 to the right and down 9 26. opens up a bit wider, no x or y movement (picture it opening like a flower blooming) 27. opens downward and is very very close to the y axis 28. opened up SUPER wide, like a large shallow bowl.