The ratio of yard material to dresses is 8 to 3. There are 27 dresses. How many yards of material is needed?

*PLEASE HELP URGENT NEED TO TURN IN TOMORROW* WILL GIVE BRAINY AND 60 OR MORE POINTS

pogonyaev

Answer:

2. 92 ounces of Sprite

3. 1/6 do not want mustard on their ham sandwiches

4. 6 hours playing volleyball

5. 32 portions

Step-by-step explanation:

2. Sam has 8 cans of Sprite. Each can is 11 2/4 ounces

We can simplify 2/4 to 1/2

Multiply the number of cans by the ounces per can

8 * 11 1/2

8 * 11.5

92 ounces

3. 1/2 of the students want ham. 1/3 of those do not want mustard

We multiply 1/2*1/3 = 1/6

1/6 of the students do not want mustard on their ham sandwiches

4. 8 hours at the beach. 3/4 of the time was spent playing volleyball

Multiply this together

8*3/4 = 8/4*3 = 2*3 = 6 hours

5. We have 4 lbs of wings. We divide it into 1/8 lbs parts

4 ÷ 1/8

Copy dot flip

4 * 8/1

32 portions

8 0

3 years ago

C. What is located at the reflection of (3,1) across

Iteru [2.4K]

Check the picture below.

6 0

2 years ago

the high school debate team is developing a logo to represent their club. A scale drawing of the logo design is presented below,

Fantom [35]

Answer:

The enlargement will be 25 times and the enlargement area will be $2250 \text{ inches}^2$ .

Step-by-step explanation:

It is given that each grid unit is equal to 3 inches. SO we have to use this scale.

The total height of the scale drawing is 21 inch and the enlargement has a height given as 105 inches. Therefore it has scale factor of 5. It means that each dimension is enlarged by 5 times the dimension in the scale drawing. So the enlargement of the logo will be 25 times and the enlargement area will be 2250 square inches.

7 0

2 years ago

What is 4(a)(c)? Calculate the answer.

Anna71 [15]

Answer: -20

4(5)(-1)=-20

5 0

2 years ago

Standing 140 feet from the base of a tree, Alejandro uses his clinometer to site the top of the tree. The reading on his clinome

Advocard [28]

Answer:

132 feet

Step-by-step explanation:

Given that Alejandro is standing at a distance of 140 feet from the base of the tree and his eyes are 6 feet above the ground.

Let AB is the height of the tree and point E is the location of his eyes which is 6 feet above from C on the ground as shown in the figure.

The distance between points A and C, AC=140 feet.

Drawing a horizontal line from point E which meets AB at point D as shown.

As ACED forms a rectangle, so

AC=DE=140 feet ...(i)

CE=AD= 6 feet ...(ii)

The height of the tree, AB=AD+DB

By using equation (ii), AB=6+DB ...(iii)

Now, given that the on watching the top of the tree, the reading on the clinometer is 42 degrees.

So, $\angle DEB = 42^{\circ}$

In triangle DEB,

$\tan 42^{\circ} = \frac {DB}{DE} \\\\\Rightarrow DB = DE \times \tan 42^{\circ} \\\\$

$\Rightarrow DB = 140 \times \tan 42^{\circ}$ [from (i)]

$\Rightarrow DB = 126$ feet

From equation (iii) the height of the tree is

AB=6+126=132 feet.

Hence, the height of the tree is 132 feet.

7 0

2 years ago