Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
3 .......................
X= 93
step by step
add 35+58=93
subtract 93 from 180 to get the missing inside angle 67
then subtract 67 from 180 to get 93
The answer to your question is 16 and 5/12
