Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.
|4r + 8| ≥ 32
Split this expression into two expressions:
First ⇒ 4r + 8 ≥ 32 and second ⇒ 4r + 8 ≤ - 32
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First expression: 4r + 8 ≥ 32
Subtract 8 from both sides.
4r ≥ 24
Divide both sides by 4.
r ≥ 6
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Second expression: 4r + 8 ≤ - 32
Subtract 8 from both sides.
4r ≤ -40
Divide both sides by 4.
r ≤ -10
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Your answer is 
12) (shaded region) 12x25 =300
( un- shaded region) 6x10=60
300-60=240
240 is the answer for #12
Answer:
<h2 /><h2>-7 , -1</h2>
Step-by-step explanation:
if the equation of line p is
4x+7y=20 then the equation of line q must be
-7 x +4y=15 because perpendicular lines have
slopes with a product of -1
