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IrinaK [193]
3 years ago
5

PLEASE HELP! I ONLY HAVE 15 MINS! WILL MARK BRAINLIEST! 20 POINTS! Suppose N coins lie heads up on a table. In one turn, you can

turn over any (N−1) coins. Is it possible that N coins could lay tails up in any number of turns, if
Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer: it is only possible if N = 2.

Step-by-step explanation:

if you have N  heads up coins.

turn one, you turn N -1 coins up.

Now you have N - 1 coins tails up and one coin heads up.

Second turn, you turn N - 1 coins, (if you select the same N - 1 coins as before, you will end in the initial situation, so now we will change one coin, this time we will select the coin that is still heads up and we will leave one of the tails up unchanged)

Then we have N - 2 coins heads up and 2 coins tails up.

Now, we can select any N -1 coins to flip, and we will end with with N - 1 coins tail up and 1 coin heads up.

and this cycle will repeat.

Then the only situation is having N = 2.

Becuase when we have N -2 coins heads up and 2 coins tails up we will have: N - 2 = 0, so we have 0 coins heads up and 2 coins tails up.

This means that the statement is only true if N = 2.

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Answer:

Z (0.10) = 1.282 (the Z-score which has 0.10 to the right, and 0.4000 between 0 and it). As a shorthand notation, the () are usually dropped, and the probability written as a subscript.

Step-by-step explanation:

hope this helped you if it did plz mark brainliest

6 0
3 years ago
A new basketball is 40% off of its original price and is now selling for $36.00. What was the original price of the basketball b
VikaD [51]
Multiply 40% and 36.00 than add what you get to 36.
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3 years ago
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
Help. and please show workout so I can know how to understand it (and both questions)
Arlecino [84]
Just remove the parenthesis since you are adding them and combine like terms
x+5+2x+3
3x+8
8 0
4 years ago
Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the
Yuliya22 [10]
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
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Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour
3 0
3 years ago
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