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Fynjy0 [20]
3 years ago
7

[{(-16)x + (-8)x }- (-10) ]• (-6)x + (-3)x What would be the correct answer?

Mathematics
1 answer:
Alborosie3 years ago
4 0

Answer: 144x^2 - 63x

Explanation:

(-16)x + (-8)x ) - (-10)• (-6)x + (-3)x

(-24x+10)*(-6)x-3x

(-24x+10)*(-6x)-3x

144x^2-60x-3x

144^2-63x

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A rectangular swimming pool can hold 1408 cubic feet of water. the pool is 22 feet long and has a depth of 4 feet. what is the w
drek231 [11]
Depth is the same thing as height for a pool.  Volume is l*w*h.
The total amount of water a pool can hold is the volume.
so take the total volume (1408) and divide it by 22 and 4.
1408/4/22=16
The width is 16 ft.
4 0
4 years ago
Read 2 more answers
Someone please help like i really need it
dangina [55]

Answer:

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6 0
2 years ago
F(x) = two divided by quantity x squared minus two x minus three
VARVARA [1.3K]
F(x) = 2÷(x² - 2x - 3)

1)
Domain:
The domain is all the values for x that will produce a real number for y
Factor the denominator to find where y is not defined:
f(x) = 2÷(x² - 2x - 3) 
f(x) = 2 ÷ (x-3)(x+1)
The domain is all real numbers except x=3 and x=-1

Range:
The range for y is all the values that y can take, given the domain.
The range is all real numbers, because y approaches both positive and negative infinite at different points on the graph. 

The y-intercept is where x=0
y= 2 ÷ (0² - 2(0) -3)
y= 2 ÷ -3 = -2/3

The x-intercept are the points at which y=0.
Let's use the factored form again: 
f(x) = 2 ÷ (x-3)(x+1)
This function has no x-intercepts. All values of X either produce a real number, or are undefined in the case of x=3 and x=-1

Horizontal Asymptotes
As X approaches inifinite, how does y behave?
f(x) = 2÷(x² - 2x - 3) 
As x approaches both positive and negative infinite, the dominate term in the denominator, x², is vastly greater than 2, and thus y approaches zero. 
The horizontal asymptote is zero, in both the positive and negative direction. 

Again, let's consult the factored form:
2 ÷ (x-3)(x+1)
There are vertical asymptotes at both x=3 and x=-1. As x approaches these numbers, depending on whether x is a little bigger or smaller than either one, y approaches positive and negative infinite, since the denominator of the function approaches zero.
Therefore, there are both positive and negative vertical asymptotes at both x=3 and x=-1

As for the graph, we'll leave that to you and the many applications that can aid in such a task!
4 0
4 years ago
Please help need today
umka2103 [35]

Answer:

50.27cm^3

Step-by-step explanation:

Given the dimensions of the cylinder as d=4cm and h=4cm, its volume can be calculated using the formula:

V=\pi r^2 h\\\\=\pi \times (4/2)^2\times 4\\\\=16\pi cm^3=50.27cm^3

Hence the volume of the cylinder is 50.27cm^3

4 0
3 years ago
Two rectangles are similar. The length and width of the first rectangle is 4 m by 5 m. The second rectangle is similar by a scal
likoan [24]
<h3>Answer:  320 square meters</h3>

===================================================

Explanation:

The scale factor 4 means the dimensions of the second rectangle are 4 times larger.

The width of 4 meters bumps up to 4*4 = 16 meters.

The length of 5 meters becomes 4*5 = 20 meters.

So a 4 by 5 rectangle is similar to a 16 by 20 rectangle.

The area of the second rectangle is therefore 16*20 = 320 square meters.

---------------

As an alternative, you can compute the area of the 4 by 5 rectangle to get 4*5 = 20. Then multiply this with 4^2 = 16 to get 16*20 = 320.

The 4^2 = 16 multiplier is the result of squaring the scale factor.

So if you know the dimensions have been multiplied by 4, then the area has been multiplied by 16.

6 0
3 years ago
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