All categories

3 years ago

What is the mean, median, mode, and range of the numbers 8,15,3,6,13,9

Mathematics

2 answers:

ivolga24 [154]3 years ago

4 0

Hello There!

To find the mean, add up all the numbers and divide according to how many numbers there are. The mean for this set would be "9"

To find the median, place the numbers in value order and find the middle. if there is no middle, add up the two numbers in middle and divide by 2. In this set, the median would be "8.5"

To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode. In this set, there would be no mode.

The range of a set of data is the difference between the highest and lowest values in the set. In this set, the range would be "12"

slega [8]3 years ago

4 0

heres your answer in a picture

You might be interested in

nika2105 [10]

Answer:

idk

Step-by-step explanation:

8 0

3 years ago

Jeremy traveled 345 miles to visit his cousin in north carolina. if he traveled at a rate of 60 miles per hour, how long did the

Orlov [11]

The trip took 5 hours and 45 mins

3 0

3 years ago

When a teacher divided her students into groups of four, she had three students remaining. when she divided them into groups of

AfilCa [17]

39 students....39/4 = 9 remainder 3
39/5 = 7 remainder 4

ur answer is 39

5 0

3 years ago

iogann1982 [59]

Answer: Step-by-step explanation: It is 9 1/2– 7 1/3=2 1/3 if that helped give a thumbs up thank you bye.

6 0

3 years ago

Chester Boles reviewed his credit card's monthly statement. It shows a $2,376.10 previous balance and this month's new purchases

ss7ja [257]

Initial balance, I = $2376.10 .

Total amount of purchase made, A = $( 875.22+65.75+45.22+21.23 ) = $1007.42 .

Total amount credit, c = $875.22 .

Fine, f = $45.30 .

Another purchase, $a=\dfrac{2376.10\times 2.5}{100}=\$ 59.4025$ .

So, balance left is :

B = I - A - f - a + c

B = 2376.10 - 1007.42 - 45.30 - 59.4025 + 875.22

B = $2139.1975

Hence, this is the required solution.

4 0

3 years ago