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CaHeK987 [17]
2 years ago
14

a square with an area of 25 in.^2 is plotted on a grid so that the bottom-left corner is at the origin. The side of the square a

re horizontal and vertical. A reflection over what line maps the square onto itself?
Mathematics
1 answer:
bazaltina [42]2 years ago
3 0

Answer:

Reflection about the vertical line x = 2.5 inches will map the square unto itself

Step-by-step explanation:

The given parameters are;

The area of the square = 25 in²

The orientation of the sides of the square are horizontal and vertical

Therefore, we have;

The area, A, of the square given by the following relation;

A = Side²

A = 25 in²

Therefore;

The area of the square = 25 = side²

The length of the sides of the square = √A = √25 = 5

The length of the sides of the square = 5 inches

The reflection of a figure that maps the figure unto itself is a reflection along the line of symmetry

One of the line of symmetry that divides the square into two similar halves is the vertical straight that passes half way through the horizontal side, which is the point 2.5 inches to the right on the x-axis with the coordinates (2.5, 0)

Therefore, reflection about the line x = 2.5 inches will map the square unto itself.

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Answer:

Step-by-step explanation:

The goal to solving any equation is to have x = {something}.  That means we need to get the x out from underneath that radical.  It's a square root, so we can "undo" it by squaring.  Square both sides because this is an equation.  Squaring both sides gives you

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Get everything on one side of the equals sign and set the quadratic equal to 0:

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Throw this into the quadratic formula to get that the solutions are x = 5 and -8.  We need to see if only one works, both work, or neither work in the original equation.

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3 years ago
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27.8 × 9.6 is equal to <span>266.88</span><span>
So, the closest would be A. 280.</span>
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Step-by-step explanation:

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<em>Hopes This Helps :)</em>

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