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3 years ago

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a dilation

Mathematics

1 answer:

Talja [164]3 years ago

4 0

Correct answer is B.

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For every 12 slices of pizza sold at Ping's Pizza Shop,

kaheart [24]

Answer:

3:5 Is the ratio because there are five pieces of cheese.

Step-by-step explanation:

If there are 12 pieces, then you can add 4 and 3 together and get 7 and then you can take 7 from 12 and get 5 which is how many cheese pieces there are. Now you know that there are 3 slices of pepperoni and 5 pieces of cheese. Therefore the ratio is 3:5.

6 0

4 years ago

If AC=12, BC=3, find CE 1) 3 square root of 3 2) 6 3) 18

azamat

Answer:

2) 6

Step-by-step explanation:

CE^2 = BC * AC

CE^2 = 3 * 12

CE^2 = 36

CE = 6

7 0

3 years ago

Read 2 more answers

Solve the formula for the red variable (a). * 23. P= a + b + c Your answer

Len [333]

Answer:

Step-by-step explanation:

7 0

3 years ago

If you add or subtract two rational numbers, is the result sometimes, always, or never rational?

lawyer [7]

Answer:

Always

Step-by-step explanation:

8 - 9 = -1

1/3 - 1/6 = 1/6 are 2 examples

8 0

3 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago