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Nookie1986 [14]
3 years ago
9

Find f. f ''(x) = −2 + 24x − 12x2, f(0) = 4, f '(0) = 18

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

good day ^-^ ///////////////

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The axis of symmetry for the function f(x) = −x2 − 10x + 16 is x = −5. What are the coordinates of the vertex of the graph?
OLga [1]

Answer:

The coordinates of the vertex are (-5, 41)

Step-by-step explanation:

For a quadratic function of the form

f(x) = ax ^ 2 + bx + c

Where a, b and c are constants and represent the coefficients of the function, then the symmetry of the parabola always passes through its vertex.

In this case we have the following parabola

f (x) = -x2 - 10x + 16

And we know that its axis of symmetry is the line x = -5

Then we know that this axis of symmetry passes through the vertex of the parabola.

Therefore, the x coordinate of the vertex is -5.

To find the coordinate in y of the vertex, we substitute x = -5 in the function.

f (-5) = -(- 5) ^ 2 -10 (-5) +16\\\\f (-5) = 41

Finally, the vertices are in the point (-5, 41).

5 0
3 years ago
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