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Ilya [14]
3 years ago
14

Given triangle XP’s is congruent to triangle dnf, find the values of x and y.

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0
ΔXPS is congruent to ΔDNF

Since they only give you two sides of ΔXPS, then you know that:
XP (4y-3)= DN (57)
XS (17x+3) = DF (54)

4y - 3 = 57
4y = 60
y = 15

17x + 3 = 54
17x = 51
x = 3

So the answers are:
x = 3
y = 15
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You must use the LCD 1/7 + 3/14 *Convert Into into like fractions and add them
Tresset [83]
The LCD of 1/17 and 3/14 is 14.

1/7 = 2/14

3/14 = 3/14

2 + 3 = 5

The denominators are the same, so it will remain the same.

= 5/14 <===

5/14 is your answer.


I hope this helps! :)
3 0
3 years ago
Read 2 more answers
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
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bearhunter [10]
1:50 => 1 part oil + 50 parts high-octane gasoline
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8 0
3 years ago
Class A has 25 pupils and class B has 28 pupils.
postnew [5]

Answer:

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3 0
2 years ago
Watch day about 75,000 people visit Paris, France. Use commutative property to write two equivalent expressions that could be us
Studentka2010 [4]

Answer:

5\times 75,000 and 75,000\times 5

Step-by-step explanation:

We have been given that about 75,000 people visit Paris, France. We are asked to write two equivalent expressions that could be used to find the number of people that visits over a 5- day period .

To find the number of people over a 5-day period, we will multiply 75,000 people by 5 as:

\text{Number of people that visits over a 5-day period}=75,000\times 5

Commutative property of multiplication states that we can multiply numbers in any order.

Upon switching the order while multiplying, we will get:

\text{Number of people that visits over a 5-day period}=5\times 75,000

Therefore, our required equivalent expressions would be 5\times 75,000 and 75,000\times 5.

5 0
3 years ago
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