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Degger [83]
3 years ago
7

URGENT PLEASE ANSWER To find the distance across a river, a surveyor chooses points A and B on one side of the river. She then c

hooses a reference point C on the opposite side of the river and finds the following measurements:
AB=100 m∡A=47∘∡B=82∘
Find the distance from point A to point C. Enter just the numerical value of the answer - do not include "AC=" or any units - and round your answer to the nearest tenth.
Mathematics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

The distance between A and C = 127.4

Step-by-step explanation:

* We have 3 different points A , B , C lets consider them as

 a vertices of a triangle ABC

- AB = 100

- m∠A = 47°

- m∠B = 82°

* To find the distance AC we can use the sin Rule

- In any triangle the ratio between the length of each side

 to the measure of each opposite angle are equal

- In Δ ABC ⇒ AB/sinC = BC/sinA = AC/sinB

* Lets do it to find the distance between A and C

∵ m∠A = 47° and m∠B = 82°

∵ The sum of the interior angles in any triangle is 180°

∴ m∠C = 180 - (47 + 82) = 180 - 129 = 51°

∵ AC/sin(82) = 100/sin(51)

∴ AC = 100 × sin(82) ÷ sin(51) = 127.423691

* AC = 127.4

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Find the domain of the following piecewise function.
il63 [147K]

Answer:

(2,8]

Step-by-step explanation:

Given

The attached piece wise function

Required

The domain

To do this, we simply consider the inequalities that bound the values of x.

The inequalities are:

2 < x < 4     4 < x < 8   and   x \ge 8

Combine the first two inequalities:

2 < x < 8    and   x \ge 8

For the inequality to be true, we must have:

2 < x \le 8

In interval notation, the inequality is:

(2,8]

6 0
3 years ago
In a transformation each point in the object is mapped to another point in the image. The following are the four types of transf
harina [27]
The answer to your question is true
6 0
3 years ago
Help I’m stuck on this question I’ve been stuck on it for a while I can’t seem to figure it out please help for ten points
Naddika [18.5K]

Answer:

\frac{1}{25}

Step-by-step explanation:

I think what it is trying to say is that it wants the solution to multiplying all of those. The (...) simply means that it wants you to continue that pattern in what you are supposed to be multiplying, but stop at \frac{24}{25}.

That would mean you are technically supposed to be multiplying:

\frac{1}{2}  \frac{2}{3} \frac{3}{4} \frac{4}{5} \frac{5}{6} \frac{6}{7} \frac{7}{8} \frac{8}{9} \frac{9}{10} \frac{10}{11} \frac{11}{12} \frac{12}{13} \frac{13}{14} \frac{14}{15} \frac{15}{16} \frac{16}{17} \frac{17}{18} \frac{18}{19} \frac{19}{20} \frac{20}{21} \frac{21}{22} \frac{22}{23} \frac{23}{24} \frac{24}{25}

That is a lot and unfortunately, none of the individual fractions can be simplified within that. The final answer would be able to be simplified, though.

Multiplying the first four shown: \frac{1}{2}\frac{2}{3} \frac{3}{4} \frac{4}{5} you end up with \frac{24}{120}. Both the numerator (top) and the denominator (bottom) are divisible by 24. Dividing top and bottom would simplify this to \frac{1}{5}.

Now, let's take the next four.

\frac{5}{6}\frac{6}{7} \frac{7}{8} \frac{8}{9} allows you to end up with \frac{1680}{3024}. Both the numerator (top) and the denominator (bottom) are divisible by 336. You are left with \frac{5}{9}.

Now, let's take the next four.

\frac{9}{10}\frac{10}{11} \frac{11}{12} \frac{12}{13}. Multiplying these gives you \frac{11880}{17160}. Both the numerator (top) and the denominator (bottom) are divisible by 1320. You are left with \frac{9}{13}.

Now, let's take the next four.

\frac{13}{14}\frac{14}{15} \frac{15}{16} \frac{16}{17}. Multiplying these gives you \frac{43680}{57120}. Both the numerator (top) and the denominator (bottom) are divisible by 3360. You are left with \frac{13}{17}.

*<em> Although I would continue to say let's take the next four, there appears to be a pattern in the simplification. The numerators we have gotten have all been four less than their denominators, and each numerator has been four more than the last. I cannot be certain, but we only have two sets of four left. If this pattern continues, the simplifications of each should be \frac{17}{21} and \frac{21}{25}. I will continue on for argument's sake, anyways.</em>

The next four are \frac{17}{18}\frac{18}{19} \frac{19}{20} \frac{20}{21}. Multiplying these, you are left with \frac{116280}{143640}. Both the numerator (top) and the denominator (bottom) are divisible by 6840. We are left with\frac{17}{21}. This is the exact guess I had made when following the pattern, and so the next one is most likely going to be the other guess as well.

Our final answer will be \frac{1}{5}\frac{5}{9} \frac{9}{13} \frac{13}{17}\frac{17}{21} \frac{21}{25} all multiplied together. We end up with \frac{208845}{5221125}. Both the numerator (top) and denominator (bottom) are divisible by 208845.

Simplified, your final answer is:  \frac{1}{25}.

* <u>NOTE:</u> that another way to solve this would just be to multiply all numbers from 1-24 together and then 2-25, but you would end up with a very large number that would be just as time consuming to simplify. To get the GCF fast, I used a GCF calculator.

6 0
3 years ago
Match each function with the corresponding function formula when h(x)=5-3x and g(x)=-3+5
Grace [21]

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

  right column to find the corresponding function formula in the

  left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

 take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

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