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andreyandreev [35.5K]
3 years ago
12

Solve the equation for y 24 = 4x + 6y

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0
There are multiple answers.
If x=1
4(1) +6y=24
24-4=6y
6y=20
y=3 1/3
Arlecino [84]3 years ago
8 0
24=4x+6y
24-4x=6y
4-2/3x=y
y=-2/3x+4
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True or false 2(a + 6) is equivalent to 2a + 13?
katen-ka-za [31]

Answer:

false

Step-by-step explanation:

5 0
3 years ago
What is the answer to 6,007,200 in exspanded form
Rzqust [24]
6,000,000 + 7,000+ 200    is your expanded form

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4 0
4 years ago
F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).​
Alex73 [517]

Answer:

a(n) = (-2)(a_{n-1})

a_{1}=5

Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = a(r)^{n-1}

Where 'a' = First term of the sequence

r = common ratio

Recursive formula of a geometric sequence is,

a(n) = (a_{n-1}).(r)^{n-1}

a(n) = (-2)(a_{n-1})

Where, a_{1}=5

So the recursive formula will be a(n) = (-2)(a_{n-1})

6 0
3 years ago
33 is 55% of what number
9966 [12]
Because percentage is the numerator divided by the denominator of a fraction times one-hundred, we can set up this equation:

\frac{33}{x} =0.55

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x = 60

So, 33 is 55% of 60.


6 0
3 years ago
Read 2 more answers
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
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