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Dahasolnce [82]
3 years ago
6

Which is the graph of y =-3StartRoot x EndRoot ?

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

3rd graph or C would be correct

Step-by-step explanation:

Took test on edge

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Multiply the polynomial (x-5)(x^2+4x-2)
madreJ [45]

Answer:

x^3-x^2-22x+10

Step-by-step explanation:

7 0
3 years ago
janetta is working out a budget. she will save 3 cents for every dollar she earns. she earns 3,173.40 per month. how much will s
lilavasa [31]

Answer:

$95.20

Step-by-step explanation:

3 cents in a dollar is 3% or 0.03.

3% of $3,173.40 =

= 0.03 * $3,173.40

= $95.202

Answer: $95.20

6 0
3 years ago
Please help, this will just take a minute of your time ❤︎ (literally)<br>(Discriminant Worksheet)
igomit [66]

Answer:

\large\boxed{x=-\dfrac{7-\sqrt{97}}{4}\ \vee\ x=-\dfrac{7+\sqrt{97}}{4}}

Step-by-step explanation:

ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{We have:}\\\\-2x^2-7x+10=4\qquad\text{subtract 4 from both sides}\\\\-2x^2-7x+6=0

a=-2,\ b=-7,\ c=6\\\\\Delta=(-7)^2-4(-2)(6)=49+48=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x=\dfrac{-(-7)\pm\sqrt{97}}{2(-2)}=\dfrac{7\pm\sqrt{97}}{-4}=-\dfrac{7\pm\sqrt{97}}{4}

6 0
3 years ago
You need to solve a system of equations. You decide to use the elimination method. Which of these is not allowed?
Serggg [28]

Answer:

B

Step-by-step explanation:

The <u>Elimination Method</u> is the method for solving a pair of linear equations which reduces one equation to one that has only a single variable.

  • If the coefficients of one variable are opposites, you add the equations to eliminate a variable, and then solve.
  • If the coefficients are not opposites, then we multiply one or both equations by a number to create opposite coefficients, and then add the equations to eliminate a variable and solve.

When multoplying the equation by a coefficient, we multiply both sides of the equation (multiplying both sides of the equation by some nonzero number does not change the solution).

So, option B is not allowed (it is not allowed to multiply only one part of equation)

8 0
3 years ago
Prove that:- (1-sinA)(1+sinA)÷(1+cosA)(1-cosA)=cot^2A​
astraxan [27]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x and cos²x = 1 - sin²x

Consider the left side

\frac{(1-sinA)(1 + sinA)}{(1+cosA)(1-cosA)} ← expand numerator/denominator using FOIL

= \frac{1-sin^2A}{1-cos^2A}

= \frac{1-(1-cos^2A)}{1-(1-sin^2A)}

= \frac{1-1+cos^2A}{1-1+sin^2A}

= \frac{cos^2A}{sin^2A}

= cot²A = right side , thus proven

6 0
3 years ago
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