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Anika [276]
2 years ago
7

What is the solution set of this compound inequality? 1 ≤ |x + 3| ≤ 4​

Mathematics
1 answer:
Anika [276]2 years ago
3 0

The solution is:

-7\leq x\leq -4 or -2\leq x\leq 1

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What is the lcm of 4 and 5
timama [110]

Answer:

20

Step-by-step explanation:

4 * 1 = 4        5 * 1 = 5

4 * 2 = 8        5 * 2 = 10

4* 3 = 12        5 * 3 = 15

4 * 4 = 16       5 * 4 = 20

4 * 5 = 20


they both go into 20 equally. there is no number lower than 20 that they both go into

8 0
3 years ago
The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solv
laiz [17]

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= <u>4.125 inches</u>

length = 2+3x = 2+3(4.125) = <u>14.375</u>

<u></u>

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)

7 0
2 years ago
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Answer:

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3 years ago
4,12,20, 28 nth term
Anna007 [38]

Answer:

8n - 4

Step-by-step explanation:

The numbers here go up in 8, so you have 8n. Afterwards, use the term and the 8 times tables. Eg. 4 is the first term and the first 8 multiple is 8, so 4-8. You have to subtract 4 from 8 to get the first term. Sorry if this didn't help but yeah...

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After 2 that x is equal to 67
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