First we put the equation in y = mx + b form where m is ur slope and b is ur y int.
2x - 5y = 10
-5y = -2x + 10
y = 2/5x - 2.......so ur slope is 2/5 and ur y int is (0,-2) <==
to find ur x int, sub in 0 for y and solve for x
2x - 5y = 10
2x - 5(0) = 10
2x = 10
x = 10/2
x = 5......and ur x int is (5,0) <==
another way to find the y int is to sub in 0 for x and solve for y...but u might as well solve it by putting it in y = mx + b form because that way u have ur slope as well.
Ths system of equations is
<span>8x+6y=48 ..............>y = 48/6 -8x/6
2x−3y=−6 ..............>y = 6/3 + 2x/3
If we use a graphic tool, we can easily check the solution,
which is
(x,y) = (3,4)
The ordered pair lies in Quadrant I</span>
Answer:
d=5
Step-by-step explanation:
1. use the distance formula: d=
2. plug in the points: d=
3. solve problem inside parentheses: d=
4. square -4 and -3: d=
5. add:d=
6. find square root: d=5
The formula can be written in the form ...
... T = (original temperature) + x·(change in temperature each minute)
The problem statement gives you the original temperature (21 °C) and tells you the temperature after 12 minutes. You have to use that information to figure out the change in temperature each minute.
The change in temperature in 12 minutes is (75 °C) - (21 °C) = 54 °C. That is the change in 12 minutes, so the change in 1 minute will be 1/12 of that:
... 54/12 = 4.5
Using this value in the equation for T, we have
... T = 21 + 4.5x