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erastovalidia [21]
3 years ago
10

What´s the answer to this expression 6/2(2+1)

Mathematics
2 answers:
Setler [38]3 years ago
8 0
The answer is 9.


Hope this helps :)
Sliva [168]3 years ago
7 0
You answer should be 9
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What is the next step to solve this equation?<br> 3x - 5 = 7
Ronch [10]

Answer:

Find the value of x the value is x=4

3x4=12

12-5=7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which linear function has the greater rate of change Y= 8x+ 3
Ad libitum [116K]
17 bc I did it trust me pls
6 0
2 years ago
PLEASE ANSWER I WILL MARK AS BRAINLIEST
Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}

(c) Banana flavouring

V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }

2. Calculate the total volume

Chlorpheniramine = 100  mL

Lidocaine               =   59

Banana flavouring =  <u>   2.5    </u>

TOTAL                    =  162 mL

3. Calculate the number of doses

\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}

5 0
2 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
3 years ago
X to the second power + 6x - 7 = 0
velikii [3]
X can equal -7 or 1
X = -7 and 1
6 0
3 years ago
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