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zimovet [89]
3 years ago
14

Which of the following statements must be true based on the diagram below? Select

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

The question is an illustration of equivalent ratios and similar triangles.

<em>The true option is: </em>\frac{WU}{WV} = \frac{UR}{VS}<em />

From the diagram, we have:

WU =  UR ---- This is so because both lines are marked once

Also, we have:

WV = VS ---- This is so because both lines are marked twice

Divide both equations

\frac{WU}{WV} = \frac{UR}{VS}

Hence, the true option is: \frac{WU}{WV} = \frac{UR}{VS}

Read more about similar triangles at:

brainly.com/question/19739157

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Kerry and three friends went out for dinner. They split a large pizza and each person had a salad and a soda. They want to leave
klio [65]

Answer:

Each person will pay $ 7.20

Step-by-step explanation:

First we find the total bill

Pizza $18.60

Salad $2.50

<u>Soda $2.25</u>

Total  $ 23.35

Sales Tax would be=  8 1/4% of $ 23.35 =$ 1.926= $ 1.93

Tip = 15% of $ 23.35= $ 3.5025

Total Bill paid= $ 23.35 + $ 1.93+ $3.50= $ 28.7825 or $ 28.78

Now dividing the bill among 4 persons = $ 28.78/4= $ 7.196 or $ 7.20

Paying the bill equally is better  and convenient than paying alone as each person gets an equal share of pizza, salad and the soda.

3 0
3 years ago
The half-life of a radioactive substance is the time required for half of a sample to undergo radioactive decay,or for the quant
NikAS [45]

Answer:

That's two half lives. 5/8 * 2 * 2 = 20/8 = 5/2 pounds7/8 * 2 * 2 = 28/8 = 7/2 pounds

Step-by-step explanation:

Brainliest plz?

4 0
2 years ago
Which expression is NOT equivalent to 2.89 × 0.6?
Rashid [163]

Answer:

(289x6)x(110x110)

Step-by-step explanation:

8 0
3 years ago
consider the triangles shown below. which of the following relationship is needed to prove that ABD ...
Brrunno [24]

A. is the answer.

the 2 triangls have AD = AC

and AB as a common side. therefore the triangls are congruent.

5 0
3 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;upstream&100&b-c&5\\&#10;downstream&100&b+c&2&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;100=(b-c)5\\&#10;\qquad \frac{100}{5}=b-c\\&#10;\qquad 20=b-c\\&#10;\qquad 20+c=\boxed{b}\\&#10;100=(b+c)2\\&#10;\qquad 50=b+c\\&#10;\qquad 50=\boxed{20+c}+c&#10;\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
3 years ago
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