Answer:
( 2, -1)
Step-by-step explanation:
(X1 + X2)/2 , (Y1 + Y2)/2
(6-2)/2 , (3-5)/2
4/2 , -2/2
2 , -1
Answer:
You will have $20,495.30
Step-by-step explanation:
If interest is compounded yearly, then n = 1; if semi-annually, then n = 2; quarterly, then n = 4; monthly, then n = 12; weekly, then n = 52; daily, then n = 365; and so forth, regardless of the number of years involved.
Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!
(x-5)(x+2)=0
roots: x=5 and x= -2
see attached photo for steps