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zimovet [89]
3 years ago
14

Which of the following statements must be true based on the diagram below? Select

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

The question is an illustration of equivalent ratios and similar triangles.

<em>The true option is: </em>\frac{WU}{WV} = \frac{UR}{VS}<em />

From the diagram, we have:

WU =  UR ---- This is so because both lines are marked once

Also, we have:

WV = VS ---- This is so because both lines are marked twice

Divide both equations

\frac{WU}{WV} = \frac{UR}{VS}

Hence, the true option is: \frac{WU}{WV} = \frac{UR}{VS}

Read more about similar triangles at:

brainly.com/question/19739157

You might be interested in
Which expression represents the greatest common factor (GCF) of 70 and 112? A. 2 x 2 x 2 x 7 B. 2 x 2 x 2 x 5 C. 2 x 7 D. 2 x 2
Mekhanik [1.2K]

Answer:

\huge\boxed{C. \ \ GCF = 2 * 7}

Step-by-step explanation:

<u>Firstly, we'll do prime factorization of these numbers.</u>

70 = 2 × 5 × 7

112 = 2 × 2 × 2 × 2 × 7

<u>So, The Greatest Common Factor can be written as:</u>

GCF = 2 × 7    <u>[Since Only one 2 and one 7 is common]</u>

<u></u>

Hope this helped!

<h2>~AnonymousHelper1807</h2>
3 0
3 years ago
11x = 57 pls tell i will give extra points for correct answer
scZoUnD [109]

Answer:

x=5 2/11

Step-by-step explanation:

its either 5 2/11 or 57/11

6 0
2 years ago
Read 2 more answers
Can anybody help me with this ?
frutty [35]

f(x) = (3/4)ˣ - 4

As x gets really negative (3/4)ˣ grows positively without bound (because it's (4/3)⁻ˣ and 4/3 > 1).

As x gets really positive (3/4)ˣ tends to zero but never quite gets there.

So (3/4)ˣ > 0 for all x

So f(x) > 0 - 4 for all x

Answer:  { y   | y > -4  }, first choice

7 0
3 years ago
6 (x+15) evaluate the expression for x=-4
Gala2k [10]
The answer would be 66.

6(-4 +15)
=
66
4 0
3 years ago
Read 2 more answers
Consider the following. (Assume that the coins are distinguishable and that what is observed are the faces or numbers that face
Nataliya [291]

Answer:

a)  P(

b)  n=(HHH, HHT, HTH, HTT, THH, THT, TTH, TTT).

Step-by-step explanation:

From the question we are told that:

3 coin are tossed

Therefore

Sample space n=(HHH, HHT, HTH, HTT, THH, THT, TTH, TTT).

Generally the sets that correspond with the result of at most one tail is therefore given as follows

P(

Therefore

The result is at most one tail when

P(

7 0
2 years ago
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