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Ray Of Light [21]
3 years ago
12

A relation is plotted as a linear function on the coordinate plane starting at point C (0,−1) and ending at point D (2,−11) . Wh

at is the rate of change for the linear function and what is its initial value?
Mathematics
2 answers:
Zina [86]3 years ago
5 0
-1 - (-11)      10
----------  =  ---
2 - 0           2

So your answer is 5 for the rate of change
atroni [7]3 years ago
5 0

Answer:

The rate of change refers to the slope of the linear function, because the slope is actually a ration between the two variables. So, to find the slope, we use its definition:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Now we replace the given points, being C the first point and D the second point:

m=\frac{-11-(-1)}{2-0}=\frac{-11+1}{2}=\frac{-10}{2}=-5

Therefore, the rate of change is -5, where the negative sign refers to a decreasing change, it's a decreasing linear function. In addition, the initial values is where the independent variable is zero, which is given in the point C (0;-1), so the initial condition is <em>y = -1</em>

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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
4 years ago
Convert.<br><br> 32 ft = <br> yd <br> ft Helpp
Nadusha1986 [10]

Answer:

10.667 yards

Step-by-step explanation:

7 0
3 years ago
According to a Department of Labor report, the city of Detroit had a 20% unemployment rate in May. Eight working-age residents w
ExtremeBDS [4]

Answer: 0.49668352

Step-by-step explanation:

Given : The unemployment rate : p = 20%= 0.20

Sample size : n =8

Let x be the binomial variable that represents the number of unemployed residents.

Binomial probability distribution formula : ^nC_xp^x(1-p)^x

The probability that at least two of the residents were unemployed :

P(x\geq2)=1-P(x

1-(^8C_0(0.2)^0(0.8)^8+^8C_1(0.2)^1(0.8)^7)

1-((1)(0.16777216)+(8)(0.2)(0.2097152))

1-(0.16777216+0.33554432)

1-(0.16777216+0.33554432)=1-0.50331648=0.49668352

Hence, Required probability =0.49668352

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3 years ago
PLEASE HELP! QUIZ QUESTION
yulyashka [42]

Answer:

I think it is a 90 degrees  angle..

Step-by-step explanation:

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Jimmy has a beginning balance of $640 in his checking account. He has a debit card transaction for $120 and withdraws $50 from t
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The new balance on Jimmys account is $468.00.
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