Answer:
I suppose we want to find the side length of the square.
We know that:
The area of the square is 49cm^2
The distance between one of the vertices of the square and the middle of the square is:
BE = 4.95cm
Now let's remember some things.
For a square of side length L, the area is:
A = L^2
and the diagonal length is:
D = √(2)*L
In this case, we know that half of the diagonal is equal to:
BE = 4.95 cm
Then the diagonal is:
D = 2*BE = 2*4.95cm = 9.9cm
And for the diagonal formula, we have:
D = 9.9cm = √(2)*L
Then the side length is:
L = 9.9cm/√(2) = 7cm
And if we check the area of this square, is:
A = L^2 = (7cm)^2 = 49cm^2
So it checks.
Then we can conclude that the sidelength of the square is 7cm, which means that:
AB = 7cm
BC = 7cm
CD = 7cm
DA = 7cm
Answer:
2y² -4y +5
Step-by-step explanation:
First you need to find the sum of y²+5y-1 and 3y²-2y+4
(y²+5y-1) + (3y²-2y+4) => y²+3y²+5y-2y-1+4
=4y²+3y+3
Next is to subtract 2y²+7y-2 from the sum calculated above in order to find the algebraic expression asked in the exercise
4y²+3y+3 -(2y²+7y-2) => 4y²-2y²+3y-7y+3+2
=2y² -4y +5
Therefore, the algebraic expression asked must be 2y² -4y +5
Answer: 84
Explanation:
Total for 5 tests = 80 x 5 = 400
Total for 4 tests = 84 + 75 + 81 + 76 = 316
5th score = 400 - 316 = 84
Answer:
I don't know what those answer choices are but the answer should be: 
Step-by-step explanation:
4-2 = 2
3 - (-2) = 5
Put the y values over the x
