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tamaranim1 [39]
3 years ago
8

I need help with this please

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0
2)
A = 1/2(10)(12) + (4 x 4)
A = 60 + 16
A = 76

answer
C . 76 in^2


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Find the circumference of a circle with radius, r = 1.5m.<br>Give your answer in terms of pi​
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Answer:

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Step-by-step explanation:

circumference = 2 × pi × r

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=》3 pi

hence it's

3\pi

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There are over 2,700 species of snakes .600 species are venomous .what would the fraction of species that are not venomous be as
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Math question below down below
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The letter A represents the smallest value in the data collection, which would be 17
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X^2(x+7) = 1/2(14x^2 + 16)
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2

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Martin earned the following scores on his last five tests.
egoroff_w [7]
<span>98, 78 , 84, 75, 91
</span>

The interquartile range formula is the first <span>quartile </span>subtracted from the third quartile:

<span>IQR = Q3 – Q1.</span>

<span><span>****************************************************
Step 1: Put the numbers in order.
75, 78, 84, 91, 98

</span><span><span>Step 2: </span><span>Find the median</span>.
</span></span>75, 78, 84, 91, 98
<span>
<span><span>Step 3: </span><span>Place parentheses around the numbers above and below the median. </span>
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
</span></span>(75, 78), 84, (91, 98)
<span>
<span><span>Step 4: </span>Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
</span></span>(75, 78), 84, (91, 98)

<span>*(75, 78) ---> (75 + 78) </span>÷ 2 = 76.5
<span>*(91, 98) ---> (91 + 98) </span>÷ 2 = 94.5
<span>
<span><span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
94.5 – 76.5 = 18

IQR = 18</span></span>
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3 years ago
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