Math question below down below

Mathematics

1 answer:

Elanso [62]3 years ago

5 0

The letter A represents the smallest value in the data collection, which would be 17

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A carton can hold 1,000 unit cubes that measure 1 inch by inch.describe the dimensions of the carton using unit cubes

Romashka-Z-Leto [24]

You've told us the volume of the carton.
That doesn't tell us the dimensions.

If the unit cubes have to exactly fit the dimensions,
then all we know is that the dimensions are integers,
and their product is 1,000.

The carton could be

1 by 1 by 1,000
1 by 2 by 500
1 by 4 by 250
1 by 5 by 200
1 by 8 by 125
1 by 10 by 100
1 by 20 by 50
1 by 25 by 40

2 by 2 by 250
2 by 5 by 100
2 by 10 by 50
.
.
and several other possible sets.

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3 years ago

What is a real life example of trigonometric ratios

Brut [27]

Answer:

Trigonometry can be used to measure the height of a building or mountains

Step-by-step explanation:

if you know the distance from where you observe the building and the angle of elevation you can easily find the height of the building. Similarly, if you have the value of one side and the angle of depression from the top of the building you can find and another side in the triangle, all you need to know is one side and angle of the triangle.

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3 years ago

For Spring Break, the Alpha Plus staff is planning a team building trip in

Elina [12.6K]

Answer:

55+(12.50×5)=117.5

30+(15× $x$ )=?

say you were inviting 5 people to fannies you would need to invite 5 1/2 people to get basically the same amount

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2 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

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3 years ago

Lisa is on a trip of 887 miles. She has already traveled 98 miles. She has 3 days left in her trip. How many miles does she need

STALIN [3.7K]

I might be wrong but, I would say about 32.6 miles a day. This could be wrong.

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3 years ago