Answer:
1 and 3/4 days are equal to 42 hours
Step-by-step explanation:
42 hours = (42 hours) (1 day / 24 hours)
42 hours = 42/24 days
Simplyfing the fraction: Dividing the numerator and denominator by 6:
42 hours = (42/6) / (24/6) days
42 hours = 7/4 days
42 hours = (4+3)/4 days
42 hours = (4/4+3/4) days
42 hours = 1 3/4 days
Answer:
![cos(\theta)=(+/-)0.84](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%290.84)
Step-by-step explanation:
we know that
----> by trigonometric identity
we have
![sin(\theta)=0.55](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D0.55)
substitute
![(0.55)^2+cos^2(\theta)=1](https://tex.z-dn.net/?f=%280.55%29%5E2%2Bcos%5E2%28%5Ctheta%29%3D1)
![cos^2(\theta)=1-(0.55)^2](https://tex.z-dn.net/?f=cos%5E2%28%5Ctheta%29%3D1-%280.55%29%5E2)
![cos^2(\theta)=0.6975](https://tex.z-dn.net/?f=cos%5E2%28%5Ctheta%29%3D0.6975)
![cos(\theta)=(+/-)\sqrt{0.6975}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%29%5Csqrt%7B0.6975%7D)
![cos(\theta)=(+/-)0.84](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%290.84)
Remember that
If the sine of angle theta is positive, then the angle theta lie on the I Quadrant or II Quadrant
therefore
If the angle theta is on the I Quadrant the cosine will be positive
If the angle theta is on the II Quadrant the cosine will be negative
Answer:
161.92
Step-by-step explanation:
Answer:
Rate = 10^(log[Ending Amount / Beginning Amount] ÷ time) -1
Rate = 10^(log(1177 / 1100) ÷ time) -1
Rate = 10^(log( 1.07) ÷ 3) -1
Rate = 10^(0.029383777685 /3) -1
Rate = 10^(0.0097945926) -1
Rate = 1.0228091219 -1
Rate = .0228091219% / hour
Source http://www.1728.org/expgrwth.htm
Step-by-step explanation:
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