Which pairs of numbers, whose sum is 35, have the largest product?

Watch help video Find the exact length of the third side. 50 10

scZoUnD [109]

Answer:

40

a triangle has 180 degrees

3 0

3 years ago

SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

boyakko [2]

Answer:

$y^2 + 8y + 16$

Step-by-step explanation:

$(6y^2 + 2y + 5) - (5y^2 - 6y - 11) =$

The first set of parentheses is unnecessary, so it can just be removed.

$= 6y^2 + 2y + 5 - (5y^2 - 6y - 11)$

To remove the second set of parentheses, you must distribute the negative sign that is to its left. It changes every sign inside the parentheses.

$= 6y^2 + 2y + 5 - 5y^2 + 6y + 11$

Now you combine like terms.

$= 6y^2 - 5y^2 + 2y + 6y + 5 + 11$

$= y^2 + 8y + 16$

7 0

3 years ago

In a company, 80% of the workers are women. If 480 men work for the company, how many workers are there in all? Use pencil

nekit [7.7K]

Answer:

The total workers are 2400.

Step-by-step explanation:

Given:

In company 80% of the workers are women.

480 workers are men.

Now, to find the total workers in all.

In first way:

If women are 80%, then men would be 100-80 = 20%.

Let the total workers be $x$ .

According to question:

$20\%\ of \ x=480$

⇒ $\frac{20}{100} \times x=480$

⇒ $0.20\times x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Now, in second way.

Again, let the total workers be $x$ .

According to question:

$x-80\%\ of\ x=480$

⇒ $x-\frac{80}{100}\times x=480$

On solving:

⇒ $x-0.80x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Therefore, the total workers are 2400.

7 0

3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago

I don’t know how to do this question pls help

sineoko [7]

Answer:

Step-by-step explanation:

Triangle P is mapped onto Q so P is the initial triangle that will transformed.

We can rotate counterclockwise 90° but we cannot do it about the origin (0,0) because the red point (5, 1) will end up at ( -1, 5) .

We see that the point (5, 1) ends up at ( -2, 4) so the center of rotation is lower than the origin.

The transformation is rotation of 90° about the point (0,-1)

5 0

3 years ago