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Andrew [12]
3 years ago
10

Which of the following lists the three named stars in order of increasing mass (lowest mass first)?

Mathematics
1 answer:
Helga [31]3 years ago
3 0

Answer:

Option (A)

Step-by-step explanation:

The Barnard's Star is usually considered to be a red dwarf, that is approximately six light-years away from the location of earth. It is present in the Ophiuchus constellation and forms the 4th proximate star to the sun.

Altair refers to the bright shining star present in the Aquila constellation. It forms the 12th brightest star that occurs in the night sky.

Spica is one of the proximate stars to the earth and that is extremely large having a mass of almost ten times the mass of the sun.

The mass of Barnard's star is= 2.864 × 10^29 kg

The mass of the Altair is= 3.56 × 10^30 kg

The mass of the Spica= 19.89 × 10^30 kg

The arrangement of these given stars in the increasing order are as follows-

Barnard's star (minimum) < Altair star < Spica star (maximum)

Hence, the correct answer is option (A).

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The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
2. You were 22 inches tall at birth, and 48 inches tall on your 8th birthday.
Leno4ka [110]

Answer:

3.25

Step-by-step explanation:because you have to divide the years with the inches so in each year i would grow about 3.25 inches

6 0
3 years ago
Anna's running time for a race was 23.1 seconds.Another runner's time was 5.86 seconds faster.Find the other Runners time ​
spin [16.1K]

Answer:

17.24

Step-by-step explanation:

Simple subtraction of decimals because the other runner was faster:

23.10

-5.86

=

17.24

7 0
3 years ago
How do you know a dilation will produce similar figures?
butalik [34]

Answer:

The corresponding side lengths of the figure will be proportional based on the scale factor.

Step-by-step explanation:

A dilation can either be an enlargement or reduction.  If the scale factor is less than one then the figure will be a reduction.  If the scale factor is one or larger then the figure will be an enlargement.  Since a dilation is basically multiplying the figure will always be proportional to the original figure.

6 0
3 years ago
Kevin is watching his hamster run and notices that the wheel makes 12 revolutions before the hamster stops running. If the radiu
AnnyKZ [126]
For this purpose would want to do 3.5•12. This equals 42. So the hamster ran 42 inches. If you need in foot form it is in 3.5 inches :) hope this helps
5 0
3 years ago
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