Answer:
Explanation:
The equation for this chemical reaction is:
Ba + Cl2 -> BaCl2
So 1 moles of Ba react with 2 mole of Cl2 to form 1 mole of BaCl2.
Given 114g of Ba and 186g of Cl2 and molar mass of 137g for Ba and 71g for Cl2,
there are 114/137 = 0.83 mole of Ba and 186/71 = 2.62 mole of Cl2.
Ba is the limiting reactant as it will be used up.
Cl2 is the reactant in excess and there will be 2.62 - 0.83*2 = 0.96 mole or 0.96*71 = 68.16g left.
Moles of BaCl2 formed = moles of Ba = 0.83
As mass of 1 mole of BaCl2 is 208.23g, 0.83 mole or 0.83 * 208.23 = 172.83g of BaCl2 can be made.
