Help, please. Formula for this problem?

Plot four lines. Each line should pass through the point

notka56 [123]

Answer:

Step-by-step explanation:

I am on the same question

3 0

2 years ago

Sorry if you can’t read it but help! If you can

drek231 [11]

Answer:

I believe that it is D

Step-by-step explanation:

A is wrong...

B is wrong (I believe)...

C is wrong...

So D is the only answer choice left.

3 0

2 years ago

Read 2 more answers

Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's

enyata [817]

Answer:

The correct answer is " $\frac{2}{7}$ ".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

$n(A) = 20$

B : final A,

$n(B) = 13$

Didn't start,

$n(A^c \cap B^c) = 12$

Now,

⇒ $n(A \cup B)=35-12$

$=23$

then,

⇒ $n(A \cup B)=20+13-23$

$=10$

hence,

The probability will be:

⇒ $P(A \cap B)=\frac{10}{35}$

⇒ $=\frac{2}{7}$

7 0

3 years ago

Consider testing H^0: u=20 against H^a: u<20 where u is the mean number of latex gloves used per week by all hospital employe

iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation

$\bar X=19.1$ represent the sample mean

$s=11.8$ represent the sample standard deviation

$n=46$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517$

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

5 0

2 years ago

Three painters can paint three walls in three minutes. how many painters are needed to paint 27 walls in nine minutes?

Advocard [28]

There is 3 variable, in this case, painters, walls and time(minutes). You need to find how many painters needed and provided information on the walls and time(minutes).

Increasing walls will cause more painter needed. It was reversed in time which was increased time will cause less painter needed.

In this case, you need to divide the variable walls with time since it reversed so: 27wall/9 minutes
It equal to : 3 walls/minute

Information provided is:
3 painters= 3 walls/3 minutes
Equal to : 3 paintes= 1 wall/minute

To make it 3 walls/minute, the painter needed will be:
(3 walls/minute) / (1 wall/minute) x 3 painters= 9 painters

Answer: 9 painters

4 0

2 years ago